Polyminos  de Périmètre 12

A number of rectangles can be made with the full set of pieces.

A variety of problems with this set is shown below.

The construction below can be used to make pentuplications of all 35 hexominoes.

Quadruplication of a dekomino with a hole in the shape of the dekomino.

Ttwo quadruplicated pentominoes with a hole in the shape of the pentomino.

1-2-3-4 problem. Take one of the pentominoes in the set and with the rest make double- triple- and quadruple-sized replicas.

1-1-2-3 problem. Create an area of 10 square units, produce a copy, a duplication and a triplication.

3-4 problem. With the whole set produce simultaneous triplication and quadruplication of an hexomino.

1-2-5 problem - take one pentomino from the set and then with the remaining pieces create double and fivefold replicas.

7-8 problem. Remove one heptomino and one octomino from the set and with the remaining pieces makes simultaneous triplications of both pieces.

Three twins problem - create three sets of pairs of congruent shapes

Two triplets problem - create two sets of three congruent shapes

Quintuplets - create 5 congruent shapes each with area 30

Sextuplets - create 6 congruent shapes each with area 25

Make two 9x9 squares with a hole in each in the shape of an hexomino

Make a 12x13 rectangle with a hole in the shape of an hexomino. All 35 problems are likely to be possible.

Sets of squares

The two-sided same chequered set consists of 48 pieces with a total area of 286.

The two-sided opposite chequered set consists of 38 pieces with a total area of 227.

The one-sided chequered set consists of 70 pieces with a total area of 412.